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Lesson 9 · 45 min

Redox reactions, electrolysis and electrochemical cells

Track electron transfer and connect electrode processes with quantitative charge and substance changes.

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Redox reactions, electrolysis and electrochemical cells

Recognising and

is electron loss and is electron gain. In, zinc loses two electrons and copper ions gain them. and occur together because electrons transferred from one species must be accepted by another in the overall process. Oxygen gain and hydrogen loss are useful introductory patterns, but electron or -state accounting covers more cases. An oxidising agent causes another species to be oxidised and is itself reduced; a reducing agent is itself oxidised. Name the actual particle rather than assuming that any substance containing oxygen is always the oxidising agent in every reaction.

Key equation
Zn+Cu²⁺→Zn²⁺+Cu

-state bookkeeping

An uncombined element has state zero. A monatomic 's state equals its charge. In many compounds oxygen is −2 and hydrogen +1, with important exceptions such as peroxides and metal hydrides. The sum equals zero for a neutral compound and the charge for a polyatomic . In sulfate SO₄²⁻, sulfur has state +6 because x + 4(−2) = −2. A rise in state indicates , and a fall indicates . states are formal bookkeeping assignments; they are not always literal atomic charges in covalent molecules. State any exception relevant to the specific formula.

Balancing half-equations

Write separate and half-equations, balancing atoms and electric charge. In an acidic aqueous example, oxygen can be balanced using H₂O, hydrogen using H⁺ and charge using electrons. Multiply half-equations so electrons cancel when added. For electron is lost per iron . For, five electrons are accepted. Combining five iron half-equations with one permanganate half-equation gives a balanced overall reaction. Check both totals and total charge. Neutral balance alone is insufficient for an ionic redox equation.

Key equation
Fe²⁺→Fe³⁺+e⁻,one
MnO₄⁻+8H⁺+5e⁻→Mn²⁺+4H₂O

What electrolysis does

Electrolysis uses an external electrical to drive a chemical change. The contains mobile ions, either molten or in a suitable solution. always occurs at the cathode and always at the anode. In an electrolytic cell the cathode connects to the negative terminal and anode to the positive terminal. Cations move toward the cathode and anions toward the anode, though water and electrode material can also participate. Solid ionic crystals do not normally conduct as electrolytes because their ions are not mobile through the lattice. Do not describe electron flow through the as though it were an ordinary metal wire.

Molten and aqueous electrolytes

In a simple molten binary salt, the metal cation can be reduced and nonmetal anion oxidised according to available species. Aqueous solutions are more complicated because water-derived processes compete. Product choice depends on electrode potentials, concentration, electrode material and kinetic effects. In aqueous copper(II) sulfate with inert electrodes, copper can deposit at the cathode while oxygen is produced at the anode under the standard school model. With copper electrodes, the anode can dissolve to replace copper ions. Concentrated chloride solution can yield chlorine at a suitable anode, while dilute or different conditions can favour oxygen. Use stated conditions rather than an absolute memorised discharge rule.

Faraday calculations

Charge passed is, with in amperes and time in seconds. One of electrons carries the Faraday constant F, approximately 96,500 C/mol for school calculations. Thus. If a metal needs z electrons to form one , deposited metal amount is Q/(zF), assuming the relevant efficiency. Mass is, where M is molar mass. For electron moles deposit one copper. Do not use atomic number as z; use the electron number in the actual half-equation.

Key equation
Q=It
n(e⁻)=QF
m=MQzF
Cu²⁺+2e⁻→Cu,two

Galvanic cells and electrode signs

A galvanic cell uses a spontaneous redox process to provide electrical output. In the elementary zinc–copper cell, zinc oxidises at the anode and copper ions reduce at the cathode. Electrons move through the external conducting path from zinc to copper. A salt bridge or suitable separator permits movement that maintains charge balance without directly mixing everything. The anode is negative and cathode positive for this galvanic operation, unlike the -driven electrolytic sign arrangement. The universal definitions remain at anode and at cathode. Electrode labels should be based on reactions, not one memorised sign that ignores cell type.

Cell potentials and reaction direction

Using tabulated standard potentials, E°cell = E°cathode − E°anode when both tabulated values are potentials. A positive value supports the written spontaneous galvanic direction under standard conditions. Do not multiply an electrode potential by a when multiplying a half-equation; potential is not an extensive amount of by itself. Actual depends on conditions, concentration and internal , so a standard table is a defined reference rather than an exact promise for any improvised cell. Rechargeable batteries reverse appropriate chemical processes under controlled charging; not every cell chemistry is safely rechargeable.

Corrosion, protection and applications

Rusting of iron involves electrochemical processes supported by moisture and oxygen, forming hydrated iron oxides rather than a single simple dry compound. Painting or coating can block contact, while sacrificial protection uses a more readily oxidised metal to protect iron under suitable electrical contact. Galvanising coats steel with zinc, which can provide both a barrier and sacrificial action. Electroplating deposits a coating onto a cathodic object using controlled solution and conditions. Electrorefining and extraction use related principles but different target reactions and designs. Industrial electrolytes and products can be hazardous, so textbook equations are not instructions for unsupervised chlorine production or battery handling.

Self-check with full reasoning

A of 2.0 A flows for 965 s, passing 1,930 C or 0.0200 mol electrons using. Copper(II) needs two electrons per , so 0.0100 mol copper can deposit; with that is 0.635 g at 100% efficiency. In the zinc–copper reaction, zinc is the reducing agent because it gives away electrons, not because it is reduced. An changing from Fe²⁺ to Fe³⁺ has lost one electron even though its positive charge increased. Track electrons explicitly whenever the terminology seems counterintuitive.

Key equation
F=96,500Cmol
M=63.5gmol

Topic revision bank

Key rules & principles

  • at anode and at cathode in every cell type.
  • Electrode signs depend on whether the cell is electrolytic or galvanic.
  • Use half-equation electron numbers in Faraday calculations.

Worked examples

Find sulfur oxidation state in SO₄²⁻.
  1. Assign oxygen −2 in sulfate.
  2. Let sulfur be x: x + 4(−2) = −2.
  3. Solve x − 8 = −2.

Answer: +6.

A 1 A current passes for 1,930 s through Cu²⁺ solution. Find copper mass at full current efficiency. Use F = 96,500 C/mol and M = 63.5 g/mol.
  1. Q = It = 1,930 C, so electron amount is 1,930/96,500 = 0.0200 mol.
  2. Cu²⁺ needs two electrons, giving 0.0100 mol Cu.
  3. Mass = 0.0100 × 63.5.

Answer: 0.635 g.

Related videos and resources

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Redox Reactions: Crash Course Chemistry #10

CrashCourse

Oxidation and reduction through electron transfer.

Electrochemistry: Crash Course Chemistry #36

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Electrochemical cells, electrolysis and plating; some electrochemical-potential detail is extension material.

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